Hi Dimitri,
What about this:
> with(a, x == y) -> a$equal
> a
x y equal
1 john mary FALSE
2 mary mary TRUE
3 mary john FALSE
4 john john TRUE
/Fredrik
On Thu, Mar 26, 2009 at 7:48 PM, Dimitri Liakhovitski <ld7...@gmail.com>wrote:
> Hello!
>
> I have a matrix a with 2 variables (see below) that contain character
> strings.
> I need to create a 3rd variable that contains True if the value in
> column x is equal to the value in column y. The code below does it.
>
> a<-data.frame(x=c("john", "mary", "mary",
> "john"),y=c("mary","mary","john","john"))
> a$x<-as.character(a$x)
> a$y<-as.character(a$y)
> a$equal<-NA
> for(i in 1:nrow(a)) {a[i,3]<-a[i,1] %in% a[i,2]}
>
> I was wondering if one can do it faster, without doing it row-by-row
> as I did it. Maybe there is a faster way to compare 2 columns?
>
> Thank you very much!
>
> --
> Dimitri Liakhovitski
> MarketTools, Inc.
> dimitri.liakhovit...@markettools.com
>
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