Tena koe Daren

One alternative:

apply(m, 1, function(x) 100*summary(factor(x,
levels=-1:1))/length(x[!is.na(x)])) 

Doubtless there are others.

HTH ....

Peter Alspach

> -----Original Message-----
> From: r-help-boun...@r-project.org 
> [mailto:r-help-boun...@r-project.org] On Behalf Of Daren Tan
> Sent: Tuesday, 24 March 2009 1:46 p.m.
> To: r-help@r-project.org
> Subject: [R] Summarizing each row into a frequency table
> 
> I have a matrix containing -1, 0, 1, however certain rows 
> will not have all 3 numbers. I have written some codes to 
> compute the frequency table of how many -1s, 0s, 1s per row, 
> but it is very ugly and not efficient if there are more than 
> 3 numbers. Please suggest.
> 
> m <- rbind(sample(0:1, replace=T, 10), sample(-1:1, 
> replace=T, 10)) m.table <- t(apply(m, 1, function(x) 
> c(sum(x==-1, na.rm=T), sum(x==0, na.rm=T), sum(x==1, 
> na.rm=T)) )) m.table <- prop.table(m.table, 1)*100
> colnames(m.table) <- -1:1
> 
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> PLEASE do read the posting guide 
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
> 

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