On Mar 21, 2009, at 2:31 PM, Ken-JP wrote:

require( zoo )

inp <- c( 5, 9, 4, 2, 1 );
m <- zoo( cbind( inp ), as.Date("2003-02-01") + (0:(length(inp)-1)));
dim( m ) # [1] 5 1
dim( m[1,,drop=FALSE] ) # [1] 1 1 - ok
dim( lag( m, -1 )) # [1] 4 1 - ok
dim( rbind( m[1,,drop=FALSE], lag(m,-1) )) # NULL - converted from zoo
matrix to zoo vector!?!?
# any way to keep the last line as a zoo matrix???

Are you sure that apply dim() is a valid method of testing for zoo-ness?

> as.zoo(rbind(m[1,,drop=FALSE], lag(m,-1) ))
2003-02-01 2003-02-02 2003-02-03 2003-02-04 2003-02-05
         5          5          9          4          2
> dim(as.zoo(rbind(m[1,,drop=FALSE], lag(m,-1) )))
NULL
> is.zoo(as.zoo(rbind(m[1,,drop=FALSE], lag(m,-1) )))
[1] TRUE


> c(m[1,,drop=FALSE], lag(m,-1) )
2003-02-01 2003-02-02 2003-02-03 2003-02-04 2003-02-05
         5          5          9          4          2
> str(c(m[1,,drop=FALSE], lag(m,-1) ))
‘zoo’ series from 2003-02-01 to 2003-02-05
  Data: num [1:5] 5 5 9 4 2
  Index: Class 'Date'  num [1:5] 12084 12085 12086 12087 12088
> dim(c(m[1,,drop=FALSE], lag(m,-1) ))
NULL


> merge(c(m[1,,drop=FALSE], lag(m,-1) ))
2003-02-01 2003-02-02 2003-02-03 2003-02-04 2003-02-05
         5          5          9          4          2
> dim(merge(c(m[1,,drop=FALSE], lag(m,-1) )))
NULL
> str(merge(c(m[1,,drop=FALSE], lag(m,-1) )))
‘zoo’ series from 2003-02-01 to 2003-02-05
  Data: num [1:5] 5 5 9 4 2
  Index: Class 'Date'  num [1:5] 12084 12085 12086 12087 12088

David Winsemius, MD
Heritage Laboratories
West Hartford, CT

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