There is aaply in the plyer package that does not require a transpose: aaply(test, 1, sort)
On Fri, Mar 13, 2009 at 11:14 AM, Kevski <p...@kevski.com> wrote: > > Oh, this seemed so simple (and I'm sure the answer will be, as usual, so > thanks in advance for enlightening me). I need to sort each row of a matrix > independent of the others. For example, > >> test <- matrix(c(8,7,1,2,6,5,9,4,3),nrow=3) >> test > [,1] [,2] [,3] > [1,] 8 2 9 > [2,] 7 6 4 > [3,] 1 5 3 > > I can get each row sorted well enough. > >> sort(test[1,]) > [1] 2 8 9 >> sort(test[2,]) > [1] 4 6 7 >> sort(test[3,]) > [1] 1 3 5 > > Now I just need the resulting matrix: > 2 8 9 > 4 6 7 > 1 3 5 > > But when I try to turn this into something more automated, I only get the > last row. > >> for(e in 1:3) sorted <- sort(test[e,]) >> sorted > [1] 1 3 5 > > I've tried various incarnations of rbind around my loop, but to no avail. > I've search my books and the forums, and I'm sure there is some nifty R > function out there, but I can't seem to find it and/or apply it correctly. > > Cheers, > Kev- > > -- > View this message in context: > http://www.nabble.com/Sorting-rows-of-a-matrix-independent-of-each-other-tp22498636p22498636.html > Sent from the R help mailing list archive at Nabble.com. > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
