On Mon, 9 Mar 2009, Vadim Ogranovich wrote:
Dear R-users,
How can I detect a NULL in a recursive list?
For a regular list I could use lapply:
lapply(list(x=NULL), is.null)
$x
[1] TRUE
However that doesn't work for structures like list(list(x=NULL)). I tried
rapply but it treats NULL as a list and discards them:
rapply(list(a=1, b=list(x=NULL)), is.null)
a
FALSE
Any suggestion?
Is this what you want?
foo <- function(x) sapply(x, function(x) if (is.list(x)) foo(x) else
length(x)==0,simplify=FALSE)
foo(list(a=list(A=1:2,B=NULL), b=list(C=NULL,D=1)))
$a
$a$A
[1] FALSE
$a$B
[1] TRUE
$b
$b$C
[1] TRUE
$b$D
[1] FALSE
HTH,
Chuck
Thank you for your help,
Vadim
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