R-FAQ 7.10
:
http://cran.r-project.org/doc/FAQ/R-FAQ.html#How-do-I-convert-factors-to-numeric_003f
--
David Winsemius
On Feb 27, 2009, at 2:56 PM, Alexy Khrabrov wrote:
I want to produce a dataframe with integer columns for elements of
string pairs:
pairs <- c("10 21","23 45")
pairs.split <- lapply(pairs,function(x)strsplit(x," "))
pdf <- as.data.frame(pairs.split)
names(pdf) <- c("p","q")
-- at this point things look good, except the columns are factors,
as I didn't change the default stringsAsFactors parameter to the
as.data.frame.
Now if I want to convert columns to integers, I get
> typeof(pdf$p)
[1] "integer"
> pdf$p
[1] 10 21
Levels: 10 21
> as.integer(pdf$p)
[1] 1 2
-- being factor levels instead of the original values. I could have
used stringsAsFactors=F and then convert the strings to integers
with as.integer all the same; what other ways are there -- e.g., is
there a way to convert integer-looking factors to integers directly,
without substituting levels?
Cheers,
Alexy
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