Hi,
you probably want to use ?all.equal instead of "=="
I couldn't run your example, though
Hope this helps,
baptiste
On 27 Feb 2009, at 10:32, Peterko wrote:
hi i am creating some variables from same data, but somewhere is
different
rouding.
look:
P = abs(fft(d.zlato)/480)^2
hladane= sort(P,decreasing=T)[1:10]/480
pozicia=c(0,0,0,0,0)
for (j in 1:5){ for (i in 2:239){
if (P[i]/480==hladane[2*j-1]){pozicia[j]=i-1}}}
period=479/pozicia
P[2]/334
[1] 0.0001279107
hladane[1]
[1] 0.0001279107
P[2]/334==hladane[1]
[1] FALSE
abs(P[2]/334 - hladane[1]) < 0.0000001
[1] TRUE
It is possible to avoid it ?
I know in this exam i can use 2x if to eliminate this rouding, but i
need to
fix it in general.
--
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_____________________________
Baptiste Auguié
School of Physics
University of Exeter
Stocker Road,
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EX4 4QL, UK
Phone: +44 1392 264187
http://newton.ex.ac.uk/research/emag
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