Combining the various approaches on the list, here's a simple
one-liner that puts the NAs at the end:

     t(apply(mat,1,function(r) { dr<-duplicated(r); c( r[!dr],
rep(NA,sum(dr)) ) ))

If you don't care where the NAs are, the following is a tad shorter
and perhaps clearer:

     mat[ t(apply(mat,1,duplicated)) ] < -NA                  # modifies mat

         -s

______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

Reply via email to