Perhaps this is what was intended?
sims <- list(length=100)
do.call(seq, sims)
seq by itself does not expect a list, but do.call() can create the
appropriate call if a list is what you want to pass to the function.
Hope this helps,
baptiste
On 5 Feb 2009, at 19:46, Uwe Ligges wrote:
Uwe Ligges wrote:
Kjetil Halvorsen wrote:
This surprised me:
reps <- 100
sims <- list(length=reps)
sims
$length
[1] 100
for(i in seq(along=sims))print(i)
[1] 1
This is R 2.8.1.
What is surprising?
sims is now a list that contains 1 element called "length" with a
numeric value of 100.
Then seq(along=sims) is exactly 1, because sims has length 1.
Hence i is printed once (1 iteration of the loop) and is 1 in the
first
(and only) iteration.
Uwe
I should have added that you probably want
sims <- vector(mode="list", length=100)
Uwe
Kjetil
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Baptiste Auguié
School of Physics
University of Exeter
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