is there a way to do that without generating a data.frame?
In my real data, I have a big data.frame and I have to compare over
different columns...
Am 25.01.2009 um 23:42 schrieb Gabor Grothendieck:
Try this:
DF <- data.frame(x, nxt = c(tail(x, -1), NA), prv = c(NA, head(x,
-1)))
DF
x nxt prv
1 1 2 NA
2 2 3 1
3 3 4 2
4 4 5 3
5 5 2 4
6 2 6 5
7 6 NA 2
subset(DF, nxt == 3 & prv == 1)$x
[1] 2
On Sun, Jan 25, 2009 at 5:29 PM, Jörg Groß <jo...@licht-malerei.de>
wrote:
Hi,
I have a quit abstract problem, hope someone can help me here.
I have a vector like this:
x <- c(1,2,3,4,5,2,6)
x
[1] 1 2 3 4 5 2 6
now I want to get the number where the previous number is 1 and the
next
number is 3
(that is the 2 at the second place)
I tried something with tail(x, -1) ...
with that, I can check the next number, but how can I check the
previous
number?
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.