One of those more elegant ways:
outer(x, 1:p, "^")
Charlotte
On Fri, Jan 9, 2009 at 4:24 PM, Sarah Goslee <sarah.gos...@gmail.com> wrote:
> Well, mat doesn't have any dimensions / isn't a matrix, and we don't
> know what p is supposed to be. But leaving aside those little details,
> do you perhaps want something like this:
>
> x<-c(23,67,2,87,9,63,8,2,35,6,91,41,22,3)
> p <- 5
> mat<- matrix(0, nrow=p, ncol=length(x))
> for(j in 1:length(x))
> {
> for(i in 1:p)
> mat[i,j]<-x[j]^i
> }
>
> Two notes: I didn't try it out, and if that's what you want rather
> than a toy example
> of a larger problem, there are more elegant ways to do it in R.
>
> Sarah
>
> On Fri, Jan 9, 2009 at 6:42 PM, Bhargab Chattopadhyay
> <bharga...@yahoo.com> wrote:
>> Hi,
>>
>>
>> Can any one please explain why the following code doesn't work? Or can
>> anyone suggest an alternative.
>> Suppose
>> x<-c(23,67,2,87,9,63,8,2,35,6,91,41,22,3)
>> mat<-0;
>> for(j in 1:length(x))
>> {
>> for(i in 1:p)
>> mat[i,j]<-x[j]^i;
>> }
>> Actually I want to have a matrix with p columns such that each column
>> will have the elements of x^(column#).
>>
>> Thanks in advance.
>>
>> Bhargab
>>
>>
>>
>
>
>
> --
> Sarah Goslee
> http://www.functionaldiversity.org
>
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