I want to combine all dataframes into one large list too...
But each dataframe is a 35 columns x varying number of rows structure
(from 2000 to >9000 rows)
I have ~1500 dataframes of these to process, and that add up to >
1.5Gb of data...

Combining dataframes into a single one require me to transform each
single dataframe into one line, but I really don't have a good
solution for the varying number of rows scenario... And also, I don't
want to stall my laptop every time I run the data set: maybe I can do
that when my prof give me a ~ 4Gb ram desktop to run the script ;)

Thanks! :)

- John

On Mon, Dec 8, 2008 at 1:36 PM, Greg Snow <[EMAIL PROTECTED]> wrote:
> In the long run it will probably make your life much easier to read all the 
> dataframes into one large list (and have the names of the elements be what 
> your currently name the dataframes), then you can just use regular list 
> indexing (using [[]] rather than $ in most cases) instead of having to worry 
> about get and assign and the risks/subtleties involved in using those.
>
> Hope this helps,
>
> --
> Gregory (Greg) L. Snow Ph.D.
> Statistical Data Center
> Intermountain Healthcare
> [EMAIL PROTECTED]
> 801.408.8111
>
>
>> -----Original Message-----
>> From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
>> project.org] On Behalf Of tsunhin wong
>> Sent: Monday, December 08, 2008 8:45 AM
>> To: Jim Holtman
>> Cc: r-help@r-project.org
>> Subject: Re: [R] Transforming a string to a variable's name? help me
>> newbie...
>>
>> Thanks Jim and All!
>>
>> It works:
>> tmptrial <- trialcompute(trialextract(
>> get(paste("t",tmptrialinfo[1,2],tmptrialinfo[1,16],".gz",sep="")) ,
>> tmptrialinfo[1,32],secs,sdm),secs,binsize)
>>
>> Can I use "assign" instead? How should it be coded then?
>>
>> Thanks!
>>
>> - John
>>
>> On Mon, Dec 8, 2008 at 10:40 AM, Jim Holtman <[EMAIL PROTECTED]>
>> wrote:
>> > ?get
>> >
>> >
>> > Sent from my iPhone
>> >
>> > On Dec 8, 2008, at 7:11, "tsunhin wong" <[EMAIL PROTECTED]> wrote:
>> >
>> >> Dear all,
>> >>
>> >> I'm a newbie in R.
>> >> I have a 45x2x2x8 design.
>> >> A dataframe stores the metadata of trials. And each trial has its
>> own
>> >> data file: I used "read.table" to import every trial into R as a
>> >> dataframe (variable).
>> >>
>> >> Now I dynamically ask R to retrieve trials that fit certain
>> selection
>> >> criteria, so I use "subset", e.g.
>> >> tmptrialinfo <- subset(trialinfo, (Subject==24 &
>> Filename=="v2msa8"))
>> >>
>> >> The name of the dataframe / variable of an individual trial can be
>> >> obtained using:
>> >> paste("t",tmptrialinfo[1,2],tmptrialinfo[1,16],".gz",sep="")
>> >> Then I get a string:
>> >> "t24v2msa8.gz"
>> >> which is of the exact same name of the dataframe / variable of that
>> >> trial, which is:
>> >> t24v2msa8.gz
>> >>
>> >> Can somebody tell me how can I change that string (obtained from
>> >> "paste()" above) to be a usable / manipulable variable name, so that
>> I
>> >> can do something, such as:
>> >> (1)
>> >> tmptrial <- trialcompute(trialextract(
>> >> paste("t",tmptrialinfo[1,2],tmptrialinfo[1,16],".gz",sep="")
>> >> ,tmptrialinfo[1,32],secs,sdm),secs,binsize)
>> >> instead of hardcoding:
>> >> (2)
>> >> tmptrial <-
>> >>
>> trialcompute(trialextract(t24v2msa8.gz,tmptrialinfo[1,32],secs,sdm),sec
>> s,binsize)
>> >>
>> >> Currently, 1) doesn't work...
>> >>
>> >> Thanks in advance for your help!
>> >>
>> >> Regards,
>> >>
>> >>     John
>> >>
>> >> ______________________________________________
>> >> R-help@r-project.org mailing list
>> >> https://stat.ethz.ch/mailman/listinfo/r-help
>> >> PLEASE do read the posting guide
>> >> http://www.R-project.org/posting-guide.html
>> >> and provide commented, minimal, self-contained, reproducible code.
>> >
>>
>> ______________________________________________
>> R-help@r-project.org mailing list
>> https://stat.ethz.ch/mailman/listinfo/r-help
>> PLEASE do read the posting guide http://www.R-project.org/posting-
>> guide.html
>> and provide commented, minimal, self-contained, reproducible code.
>

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