Try this:
for (x in c(-2, 2, 4)) {
tryCatch({
y <- log(x)
xx <- x
break
}, warning = function(w) {})
}
print(xx) # 2
On Sun, Dec 7, 2008 at 2:38 AM, Andreas Wittmann
<[EMAIL PROTECTED]> wrote:
> Dear R useRs,
>
> with the following piece of code i try to find the first value which can be
> calculated without warnings
>
> `test` <- function(a)
> {
> repeat
> {
> ## hide warnings
> suppressWarnings(log(a))
>
> if (exists("last.warning", envir = .GlobalEnv))
> {
> a <- a + 0.1
> ## clear existing warnings
> rm("last.warning", envir = .GlobalEnv)
> }
>
> if(a > 5 || !exists("last.warning", envir = .GlobalEnv))
> break
> }
>
> return(a)
> }
>
> if i run this with test(-3), i would expect a=0 as return value.
> Is it also possible to hide warnings during my function, i guess i use
> suppressWarnings in a wrong way here?
>
> Thanks and best regards
>
> Andreas
>
> ______________________________________________
> R-help@r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
