R has quite a few functions to get and manipulate filenames to facilitate exactly what you want to do. See ?files and especially the links at the end to the file name manipulation functions.
e.g. dir("pathname") lists all file names in the directory "pathname." ?list.files gives details. -- Bert Gunter -----Original Message----- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of Chris Poliquin Sent: Friday, December 05, 2008 10:02 AM To: r-help@r-project.org Subject: [R] Running R Script on a Sequence of Files Hi, I have about 900 files that I need to run the same R script on. I looked over the R Data Import/Export Manual and couldn't come up with a way to read in a sequence of files. The files all have unique names and are in the same directory. What I want to do is: 1) Create a list of the file names in the directory (this is really what I need help with) 2) For each item in the list... a) open the file with read.table b) perform some analysis c) append some results to an array or save them to another file 3) Next File My initial instinct is to use Python to rename all the files with numbers 1:900 and then read them all, but the file names contain some information that I would like to keep intact and having to keep a separate database of original names and numbers seems inefficient. Is there a way to have R read all the files in a directory one at a time? - Chris ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.