Does this satisfy?
levels(interaction(x,y))
[1] "aaa.1" "bbb.1" "ccc.1" "aaa.2" "bbb.2" "ccc.2" "aaa.3" "bbb.3"
"ccc.3"
--
David Winsemius
On Dec 5, 2008, at 8:12 AM, <[EMAIL PROTECTED]>
<[EMAIL PROTECTED]> wrote:
Hi all
(I'm sure this question has been asked before, but I cant find it).
If I have two character vectors:
x <- c("aaa","bbb","ccc")
y <- c("1","2","3")
How can I get the cartesian product of the string values?
expand.grid(x,y)
Gives me a data frame with separate columns...however, I cant seem
to get *apply to paste the column values together.
Thanks
Rory
Rory Winston
RBS Global Banking & Markets
280 Bishopsgate, London, EC2M 4RB
Office: +44 20 7085 4476
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