Since negative values could balance positives, you might need to use:
which(colSums(abs(t-v)) == 0)
> t=matrix(1:12,3,4)
> v=c(1,2,3)
> which(colSums(t-v) == 0)
[1] 1
> t
[,1] [,2] [,3] [,4]
[1,] 1 4 7 10
[2,] 2 5 8 11
[3,] 3 6 9 12
> t[1,2] <- -5
> which(colSums(t-v) == 0)
[1] 1 2
> which(colSums(abs(t-v)) == 0)
[1] 1
--
David Winsemius
Heritage Labs
On Nov 24, 2008, at 11:59 AM, <[EMAIL PROTECTED]> <[EMAIL PROTECTED]
> wrote:
How about which(colSums(t-v) == 0) ?
-----Original Message-----
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
]
On Behalf Of Salas, Andria Kay
Sent: Monday, November 24, 2008 10:04 AM
To: r-help@r-project.org
Subject: [R] matching matrix columns to a vector
I need help with (hopefully) just one more thing. I have been fussing
with this for quite some time and have decided just to give up and
ask!
I want to match a column in a matrix to a vector. I found a "which"
command that I thought would be helpful as it does the following:
g=c(1,5,3,2,7)
which(g==5)
[1] 2
As the above gave which placement in the g vector corresponded to 5
(the
second place), I need this command to give me which column in a matrix
matches to a vector.
This is just a toy example of what I am trying to do:
t=matrix(1:12,3,4)
v=c(1,2,3)
which(t[,j]==v)
This does not work, and with my "real" matrices and vectors, I was
getting outputs that did not make sense. These examples are more to
give an idea of what I am aiming to accomplish.
Thank you for all the help!!
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______________________________________________
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
