On Sat, Nov 22, 2008 at 9:04 AM, Martin Maechler
<[EMAIL PROTECTED]> wrote:
> SM> I believe Kendall tau is well-defined for this case...
>
> The real question is *WHY* there needs to be a separate package 'Kendall'
> when R itself does everything you want and does not show any problems?
Thanks for pointing me to cor(...,method="kendall"), which I did not
know about; I used the Kendall CRAN package out of pure ignorance.
In my defense, I think it is excusable ignorance, as Search on the R
Project home page finds the Kendall package (which only mentions cor
as a "See Also"). I only more recently discovered the advantages of
help.search.
By the way, is Kendall well-defined when the arguments are not
permutations of each other? cor seems to return results even in this
case:
a<-factor(c("Alice","Bob","Chris"))
b<-a[1:2]
c<-a[2:3]
cor(a,b,method="kendall")
=> 1
apparently interpreting b as c(1,2) and c as c(1,2) based on
alphabetical order (even though it is an UNordered factor), which
seems to make the value depend on the subjects' names, which I'd think
was wrong for a rank-order statistic.
Thanks again,
-s
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