David Winsemius wrote: > > On Nov 19, 2008, at 8:38 PM, Wacek Kusnierczyk wrote: > >> Jorge Ivan Velez wrote: >>> >>>> B=0:12 >>>> B >>>> >>> [1] 0 1 2 3 4 5 6 7 8 9 10 11 12 >>> >>>> ifelse(B%in%c(0:9),'A','B') >>>> >>> [1] "A" "A" "A" "A" "A" "A" "A" "A" "A" "A" "B" "B" "B" >>> >>> >> >> given the example, the solution would rather be >> >> if (B %in% as.character(0:9)) "A" else "B" >> >> or maybe >> >> if (as.numeric(B) %in% 0:9) "A" else "B" > > Er, ... The solution offered by Velez duplicates the action of the > nested ifelse expressions offered by the original poster. Your > alternatives do not. The
oops, right. should have checked agains B as a non-singleton vector. vQ ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
