On Nov 17, 2008, at 12:30 PM, David Winsemius wrote:


On Nov 17, 2008, at 11:01 AM, paul murima wrote:

heatmap.2(m, margins= c(9,9), col = bluered(64), trace=c("none"),
breaks=c(seq(-60,0,60/20)), symkey=TRUE, density.info="histogram",
cexRow=1,)
Error in image.default(1:nc, 1:nr, x, xlim = 0.5 + c(0, nc), ylim = 0.5 + :
must have one more break than colour

Thisnewbies reading of the error message and the function call:
   -request for what appears to be 64 colors
(Although my current set up does not recognize the function bluered(), I will assume that you have a package that provides bluered.)
   -3 breaks .... since 60/20 = 3

My efforts at being a substitute R interpreter were erroneous (but the inference still holds since 21 is less than 64)
> c(seq(-60,0,60/20))
[1] -60 -57 -54 -51 -48 -45 -42 -39 -36 -33 -30 -27 -24 -21 -18 -15 -12 -9 -6 -3 0
> length(c(seq(-60,0,60/20)))
[1] 21


   -an error message that says that is unacceptable.

Suggest you look at ?seq more carefully.


--
David Winsemius




Hie all.

I am working on scaling my data into a fited range of -60 0 and 60,
with increases of 20.
when i use heatmap,2 the error messgae i get is as follows

heatmap.2(m, margins= c(9,9), col = bluered(64), trace=c("none"),
breaks=c(seq(-60,0,60/20)), symkey=TRUE, density.info="histogram",
cexRow=1,)

Error in image.default(1:nc, 1:nr, x, xlim = 0.5 + c(0, nc), ylim = 0.5 + :
must have one more break than colour

Can any one help on how i can get around this problem.
Your help is most appreciated.

Rockie

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and provide commented, minimal, self-contained, reproducible code.

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and provide commented, minimal, self-contained, reproducible code.

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