on 11/13/2008 09:39 AM mentor_ wrote:
> Hi,
>
> two days ago I have asked the list if there is a better way to plot a matrix
> using
> the following plot command:
>
> plot(matrix[1,], type="l")
> for (i in 2:dim(matrix)[1]) {
> lines(matrix[i,], type="l")
> }
>
> I have been told to use the matplot function, but unfortunately I matplot
> does not plot my matrix
> as I would like the matrix to be plotted...
> Each row in the matrix should be plotted as a time series plot. The columns
> should reflect the "time"
> The matrix looks like this:
>
> [,1] [,2] [,3] [,4] [,5] [,6]
> [1,] 10.795525 17.742121 -1.668664 7.410594 10.229107 -0.7402613
> [2,] 9.335885 10.472469 9.503561 9.815167 16.073518 21.1387238
> [3,] 16.818605 5.354479 10.921837 5.202947 4.730314 2.3975041
> [4,] 9.773960 10.081033 3.538419 16.913288 10.623028 7.8052165
> [5,] 8.473132 13.775806 3.739209 15.224250 6.339220 7.3409747
>
> I tried this with matplot:
> m <- matrix(rnorm(30, 10, 5), ncol=6)
> time <- matrix(rep(1:6,5), nrow=5, byrow=TRUE)
> matplot(time, m, type="l", col="black")
>
> Any help would be appreciate!
> Thanks!
What you really want is simply:
matplot(m, type = "l", col = "black")
Note from ?matplot:
x,y vectors or matrices of data for plotting. The number of rows
should match. _If one of them are missing, the other is taken as
y and an x vector of 1:n is used_
Thus, if you simply pass the matrix 'm', an x vector of 1:5 is used by
default and each column of 'm' is plotted against 1:5.
If you, for some reason, wanted to create the 'time' matrix, it should be:
> matrix(1:5, nrow = 5, ncol = 6)
[,1] [,2] [,3] [,4] [,5] [,6]
[1,] 1 1 1 1 1 1
[2,] 2 2 2 2 2 2
[3,] 3 3 3 3 3 3
[4,] 4 4 4 4 4 4
[5,] 5 5 5 5 5 5
so that the 'x' values are ordered within each column, rather than by
row. However, note that based upon the above, you do not need a matrix.
A vector of 1:5 would suffice, as in:
matplot(1:5, m, type = "l", col = "black")
HTH,
Marc Schwartz
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