But the problem is that I have MANY vectors, whose names are of some
specific pattern. It is not good for us to write a very long expression.
vectors <- list(ls(pattern="xyz")) didn't get what I want.
Leon
Wacek Kusnierczyk wrote:
... but it seems to me a better solution to have the vectors you need in
a list, and then iterate over the list, rather than have to look the
vectors up by name:
vectors = list(v1, v2, 1:10, ...)
u = NULL
for (v in vectors) u = union(u, v)
when you use get, you start to explicitly play with environments, and
you should be knowing what you do, otherwise ugly surprizes await.
vQ
Leon Yee wrote:
Cool! It works!
Thank you very much!
Leon
Yihui Xie wrote:
You need to get() their elements instead of merely using variable names.
Regards,
Yihui
--
Yihui Xie <[EMAIL PROTECTED]>
Phone: +86-(0)10-82509086 Fax: +86-(0)10-82509086
Mobile: +86-15810805877
Homepage: http://www.yihui.name
School of Statistics, Room 1037, Mingde Main Building,
Renmin University of China, Beijing, 100872, China
On Fri, Oct 17, 2008 at 6:23 PM, Leon Yee <[EMAIL PROTECTED]> wrote:
Dear all,
I have a question about "union". "union" handles two vectors'
elements to
get their union, but I have many vectors and I want to get the union
of all
of them. So I wrote a loop:
all <-c();
for(var in ls(pattern="xyz"))
# all of the vectors with pattern of "xyz"
{
all <- union(all, var);
}
but the result is like this: ("xyzblabla1", "xyzblabla2", "abcxyz",
... ) --
just a collection of the variable names, not the union of their
elements.
How can I solve this problem?
thanks!
Leon
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