Not an answer but I find that DF <- data.frame(let = letters[1:3], num = 1:3, stringsAsFactors = FALSE) is very handy. Damn it, if I want a factor I'll tell the machine I do :)
Or you can also set this option globally with options(stringsAsFactors = TRUE) Gabor Grothendieck warns that this last can possibly cause problems when using R programs from other places. I ran into this problem once with reshape. --- On Thu, 10/9/08, Michael Kubovy <[EMAIL PROTECTED]> wrote: > From: Michael Kubovy <[EMAIL PROTECTED]> > Subject: Re: [R] Turn factors to numeric > To: "Charilaos Skiadas" <[EMAIL PROTECTED]> > Cc: "r-help" <r-help@r-project.org> > Received: Thursday, October 9, 2008, 8:25 AM > Dear R-helpers, > > The FAQ in question says: > > > It may happen that when reading numeric data into R > (usually, when > > reading in a file), they come in as factors. If f is > such a factor > > object, you can use > > as.numeric(as.character(f)) > > to get the numbers back. More efficient, but harder to > remember, is > > > > as.numeric(levels(f))[as.integer(f)] > > I wonder why the R Core group did not choose to make such a > useful > operation simpler for the user (i.e., something like a > factor2numeric() function that would be a wrapper to the > more > efficient command). > _____________________________ > Professor Michael Kubovy > University of Virginia > Department of Psychology > USPS: P.O.Box 400400 Charlottesville, VA 22904-4400 > Parcels: Room 102 Gilmer Hall > McCormick Road Charlottesville, VA 22903 > Office: B011 +1-434-982-4729 > Lab: B019 +1-434-982-4751 > Fax: +1-434-982-4766 > WWW: http://www.people.virginia.edu/~mk9y/ > > On Oct 9, 2008, at 7:16 AM, Charilaos Skiadas wrote: > > > R-FAQ 7.10: > > > http://cran.r-project.org/doc/FAQ/R-FAQ.html#How-do-I-convert-factors-to-numeric_003f > > > > On Oct 9, 2008, at 6:59 AM, joseph kambeitz wrote: > > > >> I am having some problems while trying to fit > simple data. > >> I aggregated some data using: > >> data1 <- aggregate(data1$T2, > list=(SOA=data1$SOA), mean) > >> > >> unfortunatly this coerces my variable SOA into a > factor. Therefore > >> when a afterwards try to fit a simple equation to > my variable T2 > >> using a formula on SOA i get a error because SOA > is a factor and > >> that "*" is not meaningful for > factors... > >> > >> nls(T2 ~ a + b*SOA, start=list(a=1,b=1), > data=data1, trace=TRUE) > >> > >> In fact SOA is a numeric variable (in my > experiments it is the time > >> that passed!) so i would like to re-coerce it into > a numeric > >> variable to do the fit or to find a method to do > the fit even > >> though SOA is a factor. Thanks a lot for your > help! > >> > >> Best > >> Jokel > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, > reproducible code. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.