Duncan,
Thank you so much. It is exactly what I was looking for. However, for some
reason, indices() does not work ("Error: could not find function "indices").
I used which(), it worked.
Thanks again for the help,
Julia
Duncan Murdoch-2 wrote:
>
> On 08/10/2008 2:36 PM, liujb wrote:
>> Dear R users,
>>
>> I have this vector that consists numeric numbers. Is there a command that
>> detects the repeated numbers in a vector and returns the index of the
>> repeated numbers (or the actual numbers)? For example, v <- c(3,4,5,7,4).
>> The command would return me index 2 and 5 (or the repeated number, 4).
>
> duplicated() comes close, but the first occurence doesn't count as a
> duplication:
>
> > duplicated(v)
> [1] FALSE FALSE FALSE FALSE TRUE
>
> To convert into values, you can index v by it:
>
> > v[duplicated(v)]
> [1] 4
>
> and to find which indices are duplicated,
>
> > indices <- seq_along(v)
> > indices[duplicated(v)]
> [1] 5
>
> If you really want to include the the first one, you can do something
> like:
>
> > indices[ v %in% v[duplicated(v)] ]
> [1] 2 5
>
>
> Duncan Murdoch
>
> ______________________________________________
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> PLEASE do read the posting guide
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>
>
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