On 01-Oct-08 10:44:10, [EMAIL PROTECTED] wrote:
>> I am new to R and I would like to get the day of the year from
>> numerous data in the following form: %a %d/%b/%Y %H:%M:%S (for
>> example from Tu 10/Jul/2007 21:59:13 I would like to get 191)
>>
>> Whatever I try, I get NAs.
>
> The problem is th 'Tu' bit. Abbreviated day-of-week names and three
> letters long. You'll have to replace/ delete them.
>
> datestr <- "Tu 10/Jul/2007 21:59:13"
> newdatestr <- sub("Tu", "Tue", datestr)
> dateval <- strptime(newdatestr, "%a %d/%b/%Y %H:%M:%S")
> dateval$yday #190
In addition to the above: BEWARE that strptime(...)$yday counts
upwards from 0 to 364 (normal year) or 365 (leap year). In other
words, 1 Jan is day 0.
Hence Richard got the result 190 where you expected 191.
So add 1 to get the answer everyone expects!
Best wishes,
Ted.
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E-Mail: (Ted Harding) <[EMAIL PROTECTED]>
Fax-to-email: +44 (0)870 094 0861
Date: 01-Oct-08 Time: 12:24:12
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