Try Ryacas: > library(Ryacas) > A <- Sym("A"); B <- Sym("B"); X <- Sym("X"); Y <- Sym("Y"); K <- Sym("K") > Solve(K==(sin(A) * sin(B) ) + ( cos(A) * cos(B) * cos ( X - Y ) ), "X") [1] "Starting Yacas!" expression(list(X == Y + acos((K - sin(A) * sin(B))/(cos(A) * cos(B))), X == Y - acos((K - sin(A) * sin(B))/(cos(A) * cos(B)))))
See home page at: http://ryacas.googlecode.com On Wed, Sep 10, 2008 at 9:09 AM, milton ruser <[EMAIL PROTECTED]> wrote: > Dear R-gurus, > I know that it is not a R problem, but as need > to implement some solution for this on R, I would > like to know if someone help me on how to isolate > X on the expression below. > > K=(sen A * sen B ) + ( cos A * cos B * cos ( X - Y ) ) > > Any help are welcome > > mitinho astronauta > brazil > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.