Try this:
str <- " 1975 01 7711.16"
# Find the position of the space in string
gregexpr("[[:space:]]", str)
# Remove the space
gsub("[[:space:]]", "", str)
On Wed, Sep 10, 2008 at 9:07 AM, Megh Dal <[EMAIL PROTECTED]> wrote:
> I have following
>
> " 1975 01 7711.16"
>
> Here I need to identify where the <space> is there and then concatenate
> rest of the digits without <space>, i.e. I want to have "1975017711.16". Is
> there any R function?
>
> Regards,
>
> ______________________________________________
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> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
--
Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40" S 49° 16' 22" O
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