N. Lapidus wrote:
> You were very close to an answer :
> as.vector(unlist(df[1,]))
>
>
I'd use as.character() there, for clarity. It's not easy to remember
what as.vector on a factor variable does.
Also notice that the original post has serious confusion about what the
data structures are:
df is data frame, not a matrix
df[1,] is a one-row data frame, not a 1-d vector
the components of df are factors, not character vectors
A data frame is a kind of list, and lists are a kind of vector, hence
as.vector does nothing to df[,1]. The unlist() function applied to
factors will take the union of their level sets and concatenate the values.
An alternative way is to make sure that you have a character matrix to
begin with:
> as.matrix(df)
x y
[1,] "a" "d"
[2,] "b" "e"
[3,] "c" "f"
> as.matrix(df)[1,]
x y
"a" "d"
(but beware the rather surprising
> as.character(df)
[1] "1:3" "1:3"
!!!)
> Nael
>
> On Wed, Aug 27, 2008 at 7:53 AM, Ronnen Levinson <[EMAIL PROTECTED]> wrote:
>
>
>> Hi.
>> How do I convert a one-dimensional array of characters to a character
>> vector? In the example below I am trying to get the result c("a","d").
>> The
>> function as.vector() returns the same one-dimensional array, and unlist()
>> returns something more complicated than I seek.
>> Yours truly,
>> Ronnen.
>> P.S. E-mailed CCs of posted replies appreciated.
>> > df=data.frame(x=letters[1:3],y=letters[4:6])
>> > df
>> x y
>> 1 a d
>> 2 b e
>> 3 c f
>> > df[1,]
>> x y
>> 1 a d
>> > as.vector(df[1,])
>> x y
>> 1 a d
>> > unlist(df[1,])
>> x y
>> a d
>> Levels: a b c d e f
>> > c("a","d") # desired result
>> [1] "a" "d"
>>
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