Hi,
I find convenient to use a custom function for this:
sample.df <-
function (df, N = 1000, ...)
{
df[sample(nrow(df), N, ...), ]
}
sample.df(daf1,1000)
Hope this helps,
baptiste
On 25 Aug 2008, at 12:31, Martin Hvidberg wrote:
I have a data frame (daf1), that holds +80000 records, and 10
variables (i.e. 10 columns and some 80000 rows)
length(daf1)
[1] 10
length(daf1[,1])
[1] 83805
I would like to sample() e.g. 10000 records from this. I use:
daf2 <- sample(daf1, 1000, replace = FALSE, prob = NULL)
Error in `[.data.frame`(x, .Internal(sample(length(x), size,
replace, :
cannot take a sample larger than the population when 'replace =
FALSE'
As length(daf1) is 10, it thinks I'm taking 10000 samples from a
size 10 population... Arghhh
How do I go about sampeling from a data frame?
:-( Martin
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_____________________________
Baptiste AuguiƩ
School of Physics
University of Exeter
Stocker Road,
Exeter, Devon,
EX4 4QL, UK
Phone: +44 1392 264187
http://newton.ex.ac.uk/research/emag
______________________________________________
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.