Perhaps you want
val <- substitute("value" == a, list(a = a))
legend(6, 5, do.call("expression", list("Legend", val)), bty = 'n')
?
Your first attempt is a character vector and your second fixed up quote
and substitute. But more likely would be
legend(6, 20, val, bty="n", title="Legend")
On Mon, 11 Aug 2008, Monica Pisica wrote:
Hi,
I have a graph and I would like to write some values inside the legend
that were saved in a variable. Please revise the code below in which
I've wrote 2 different legends, but I am not happy with either of them.
What I want is a legend with tile "Legend" and underneath a line with a
name and a value like that: value = 2.
#Code begin:
# -------------------
a = 2 # result of a function for example
plot(1:10, a*(1:10))
legend(1, 20, c("Legend", bquote(value ==.(a))), bty = 'n')
val <- substitute("value" ==.(a), list(a = a))
legend(6, 5, do.call("expression",list("Legend", val)), bty = 'n')
# -------------------
# Code end
In the first legend I don't like that value == 2 instead of value = 2, in the
second legend, obviously I don't like the period and the brackets around the
value of a.
Thanks for any help,
Monica
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--
Brian D. Ripley, [EMAIL PROTECTED]
Professor of Applied Statistics, http://www.stats.ox.ac.uk/~ripley/
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