If you are using zoo for this you can do: library(zoo)
set.seed(1) x <- zoo(rnorm(7), as.numeric(1:7)) y <- zoo(rnorm(4), c(1, 2, 6, 7)) xy <- merge(x,y) xy$y - xy$x # or if you just want the difference at times existing in both y - x On Sat, Aug 2, 2008 at 5:16 PM, <[EMAIL PROTECTED]> wrote: > I like the fact that in subtracting two time series objects that there is > some effort to align the series. So if I have a time series of that begins at > 1 and one that begins at 2 a subtraction operation makes sure that the proper > values are subtracted. But I am unclear as to the best way to build a time > series with "holes". say that I have data for "day" 1,2,6,7 in one time > series and 1,2,3,4,5,6,7 in another. How do I construct the time series and > indicate the missing data for 3,4,5 as in the first series? Eventually I > would like to find the difference between the two series. If the difference > is series 2 minues series one, then for the indexes of 3,4,5 in the resultant > difference it would just be the series 2 value. The resultant series would > have a length of 7. > > Thank you. > > Kevin > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
