Dear Gundala,
Try this:
x=as.matrix(read.table(textConnection("
4.482909e-01 0.55170907
9.479594e-01 0.05204063
8.923553e-01 0.10764474
9.295003e-01 0.07049966
8.880434e-01 0.11195664
9.197367e-01 0.08026327
9.431232e-01 0.05687676
9.460356e-01 0.05396442
6.053829e-01 0.39461708
9.515173e-01 0.04848268"),header=FALSE,sep=""))
index=apply(x,1,function(x) ifelse(x[1]>x[2],'Group1','Group2'))
index
[1] "Group2" "Group1" "Group1" "Group1" "Group1" "Group1" "Group1" "Group1"
"Group1" "Group1"
HTH,
Jorge
On Thu, Jul 31, 2008 at 11:00 PM, Gundala Viswanath <[EMAIL PROTECTED]>wrote:
> Hi,
>
> I have the following (M x N) matrix, where M = 10 and N =2
> What I intend to do is to group index of (M) based on this condition
> of "x_mn" , namely
>
> For each M,
> If x_m1 > x_m2, assign index of M to Group1
> otherwise assign index of M into Group 2
>
>
> > x
> [,1] [,2]
> [1,] 4.482909e-01 0.55170907
> [2,] 9.479594e-01 0.05204063
> [3,] 8.923553e-01 0.10764474
> [4,] 9.295003e-01 0.07049966
> [5,] 8.880434e-01 0.11195664
> [6,] 9.197367e-01 0.08026327
> [7,] 9.431232e-01 0.05687676
> [8,] 9.460356e-01 0.05396442
> [9,] 6.053829e-01 0.39461708
> [10,] 9.515173e-01 0.04848268
>
> Is there a simple way to do it in R?
> - Gundala Viswanath
> Jakarta - Indonesia
>
> ______________________________________________
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>
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