Here is one approach with base R, starting with your first 2 lines,
then a 1-liner
df1 = data.frame(x = 1:20,
y = rep(letters[1:5],4),
w = c(rep(LETTERS[1],10), rep(LETTERS[2],10)),
z = rnorm(20),
stringsAsFactors = FALSE)
df2 = data.frame(x = sample(df1$x, 5))
df2 <- merge(df2, df1, by="x", sort=FALSE)[,c("x","z")]
HTH,
Eric
On Tue, Jan 20, 2026 at 12:25 PM Luigi Marongiu
<[email protected]> wrote:
>
> Dear all,
> this is a basic question but I could not find a specific answer online.
> I have a dataframe (df1) with, in particular, an identification value
> `x` and an output value `z`.
> I also have another dataframe (df2) that shares `x`.
> I need to assign `z` to df2 where df1$x is equal to df2$x.
> What would be a straightforward way of doing this?
> I can do it, but selecting one element at a time, checking the
> identity of the x elements, and then assigning z. There should be a
> more R way...
> Thank you
>
>
> ```
> df1 = data.frame(x = 1:20,
> y = rep(letters[1:5],4),
> w = c(rep(LETTERS[1],10), rep(LETTERS[2],10)),
> z = rnorm(20),
> stringsAsFactors = FALSE)
> df2 = data.frame(x = sample(df1$x, 5))
> df2$z = NA
> for (i in df1$x) {
> df2$z[df2$x==i] = df1[df1$x==i,]$z
> }
> ```
>
> ______________________________________________
> [email protected] mailing list -- To UNSUBSCRIBE and more, see
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide https://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
______________________________________________
[email protected] mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide https://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.