And then lapply over out. On Mon, Jul 28, 2008 at 6:41 PM, Gabor Grothendieck <[EMAIL PROTECTED]> wrote: > rollapply along an index: > > library(zoo) > z <- zoo(matrix(101:110, 5), 201:205) > tt <- time(z) > zz <- zoo(seq_along(tt), tt) > out <- rollapply(zz, 3, function(ix) list(z[ix,])) > str(out) # list of zoo objects > > > On Mon, Jul 28, 2008 at 5:03 PM, rcoder <[EMAIL PROTECTED]> wrote: >> >> >> rcoder wrote: >>> >>> Hi everyone, >>> >>> Is there a way to perform a rollapply operation on a time series data >>> matrix and preserve the time frame? Currently, when I apply rollapply in >>> its standart form, the date column is no longer present in the o/p matrix. >>> >>> Thanks, >>> >>> rcoder >>> >> >> -- >> View this message in context: >> http://www.nabble.com/rollapply%28%29-opertation-on-ts-matrix-tp18694735p18699707.html >> Sent from the R help mailing list archive at Nabble.com. >> >> ______________________________________________ >> R-help@r-project.org mailing list >> https://stat.ethz.ch/mailman/listinfo/r-help >> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html >> and provide commented, minimal, self-contained, reproducible code. >> >
______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
