Thanks for your answers. I was not aware of the R function expm1().
I’m completely aware that 1 == 1 - 5e-19. But I was wondering why pt() returns something smaller than double.eps. For students who will use this exercise, it is disturbing to find 0 or 5e-19 : yet it will be a good exercise to find that these quantities are equalled. Regards, Christophe > Le 25 oct. 2025 à 12:14, Ivan Krylov <[email protected]> a écrit : > > В Sat, 25 Oct 2025 11:45:42 +0200 > Christophe Dutang <[email protected]> пишет: > >> Indeed, the p-value is lower than the epsilon machine >> >>> pt(t_score, df = n-2, lower=FALSE) < .Machine$double.eps >> [1] TRUE > > Which means that for lower=TRUE, there will not be enough digits in R's > numeric() type to represent the 5*10^-19 subtracted from 1 and > approximately 16 zeroes. > > Instead, you can verify your answer by asking for the logarithm of the > number that is too close to 1, thus retaining more significant digits: > > print( > -expm1(pt(t_score, df = n-2, lower=TRUE, log.p = TRUE)), > digits=16 > ) > # [1] 2.539746620181249e-19 > print(pt(t_score, df = n-2, lower=FALSE), digits=16) > # [1] 2.539746620181248e-19 > > expm1(.) computes exp(.)-1 while retaining precision for numbers that > are too close to 0, for which exp() would otherwise return 1. > > See the links in > https://cran.r-project.org/doc/FAQ/R-FAQ.html#Why-doesn_0027t-R-think-these-numbers-are-equal_003f > for a more detailed explanation. > > -- > Best regards, > Ivan > (flipping the "days since referring to R FAQ 7.31" sign back to 0) ______________________________________________ [email protected] mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide https://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
