Sorry, hit send by accident. The 2-line version is: x <- do.call(rbind, x) dim(x) <- NULL
Cheers, Bert On Thu, Sep 26, 2024 at 9:23 PM Bert Gunter <bgunter.4...@gmail.com> wrote: > How about: > as.vector(do.call(rbind,x)) > > Cheers, > Bert > > > > > However, I much prefer a 2 line version: > > On Thu, Sep 26, 2024 at 8:56 PM Rolf Turner <rolftur...@posteo.net> wrote: > >> >> I have (toy example): >> >> x <- list(`1` = c(7, 13, 1, 4, 10), >> `2` = c(2, 5, 14, 8, 11), >> `3` = c(6, 9, 15, 12, 3)) >> and >> >> f <- factor(rep(1:3,5)) >> >> I want to create a vector v of length 15 such that the entries of v, >> corresponding to level l of f are the entries of x[[l]]. I.e. I want >> v to equal >> >> c(7, 2, 6, 13, 5, 9, 1, 14, 15, 4, 8, 12, 10, 11, 3) >> >> I can create v "easily enough", using say, a for-loop. It seems to me, >> though, that there should be sexier (single command) way of achieving >> the desired result. However I cannot devise one. >> >> Can anyone point me in the right direction? Thanks. >> >> cheers, >> >> Rolf Turner >> >> -- >> Honorary Research Fellow >> Department of Statistics >> University of Auckland >> Stats. Dep't. (secretaries) phone: >> +64-9-373-7599 ext. 89622 >> Home phone: +64-9-480-4619 >> >> ______________________________________________ >> R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see >> https://stat.ethz.ch/mailman/listinfo/r-help >> PLEASE do read the posting guide >> https://www.R-project.org/posting-guide.html >> and provide commented, minimal, self-contained, reproducible code. >> > [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide https://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
