Here is one approach for using the average of each interval:
> # generate some test data; assume 1.0 is one degree
> min.5 <- 5 / 60 # portion of degree for 5 minutes
> n <- 100 # number of data points
> myData <- cbind(interval=seq(0, by=min.5, length=n), value=runif(n))
> # create breaks every 0.5 degrees and make sure the range covers everything
> breaks <- c(seq(min(myData[,'interval']), max(myData[, 'interval']), by=0.5),
> Inf)
> # create the 'cuts' in the data
> myCuts <- cut(myData[, 'interval'], breaks, include.lowest=TRUE)
> # samples in each period
> table(myCuts)
myCuts
[0,0.5] (0.5,1] (1,1.5] (1.5,2] (2,2.5] (2.5,3] (3,3.5] (3.5,4]
(4,4.5] (4.5,5] (5,5.5] (5.5,6] (6,6.5] (6.5,7] (7,7.5]
7 6 6 6 6 6 6 6
6 6 6 6 6 6 6
(7.5,8] (8,Inf]
6 3
> # compute the average of each sample
> aggregate(myData[, 'value'], list(myCuts), FUN=mean)
Group.1 x
1 [0,0.5] 0.6159838
2 (0.5,1] 0.3393176
3 (1,1.5] 0.7425675
4 (1.5,2] 0.7360632
5 (2,2.5] 0.5296324
6 (2.5,3] 0.4908095
7 (3,3.5] 0.4415784
8 (3.5,4] 0.4930957
9 (4,4.5] 0.4455074
10 (4.5,5] 0.5126061
11 (5,5.5] 0.7512261
12 (5.5,6] 0.5406761
13 (6,6.5] 0.4331468
14 (6.5,7] 0.4721029
15 (7,7.5] 0.5113987
16 (7.5,8] 0.4565146
17 (8,Inf] 0.1510198
>
>
On Sat, Jul 26, 2008 at 7:07 PM, Steve Murray <[EMAIL PROTECTED]> wrote:
>
> Dear all,
>
> I have gridded data at 5' (minutes) resolution, which I intend to coarsen to
> 0.5 degrees. How would I go about doing this in R? I've had a search online
> and haven't found anything obvious, so any help would be gratefully received.
>
> I'm assuming that there will be several 'coarsening' techniques available -
> I'm after something fairly simple, which for example, just takes an average
> of each 0.5 degree portion of the current dataset.
>
> If someone is able to point me in the right direction, then I'd be very
> grateful.
>
> Many thanks,
>
> Steve
>
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--
Jim Holtman
Cincinnati, OH
+1 513 646 9390
What is the problem you are trying to solve?
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