Hy Richie, thank you for the quick response.
Unfortunately my problems hold on.
Once again: 2 vectors (numeric) including NAs
My intention: I want to replace the values of vector a that are smaller
than 2 and larger than 3 into NAs only in case vector b equals 1
a <- c(rep(seq(1,4),4),NA,NA)
b <- c(rep(seq(1,2),7),NA,NA,1,2)
data.frame(a,b)
a b
1 1 1
2 2 2
3 3 1
4 4 2
5 1 1
6 2 2
7 3 1
8 4 2
9 1 1
10 2 2
11 3 1
12 4 2
13 1 1
14 2 2
15 3 NA
16 4 NA
17 NA 1
18 NA 2
me <- a[b==1][a[b==1]<2 | a[b==1]>3]
you <- a[a[b==1]<2 | a[b==1]>3]
There are some differences
length(me)
[1] 7
length(you)
[1] 12
me
[1] 1 1 1 1 NA NA NA
you
[1] 1 3 1 3 NA NA NA 3 1 3 NA NA
Your vector is containing the value 3. And in our case this value would
be replaced by NA.
I belive that in this case
a[b==1]<2 | a[b==1]>3
[1] TRUE FALSE TRUE FALSE TRUE FALSE TRUE NA NA NA
Would be applied on the FIRST 10 values of a and then will be repeated.
Maybe it would be possible to do something like
a[(a<2 & b==1) | (a>3 & b==1)]
Is it allowed to construct double indices like
vector[][] ?
> Assume 2 vectors (numeric) including NAs
>
> a <- c(rep(seq(1,4),4),NA,NA)
> b <- c(sample(1:2,14,replace=T),NA,NA,1,2)
>
> I want to replace the values of vector a that are smaller than 2 and
> larger than 3 into NAs only in case vector b equals 1
>
> a[b==1][a[b==1]<2 | a[b==1]>3] <- NA
> The following error accurse:
> NAs are not allowed in subscripted assignments
You were nearly right - you just had an extra index that you didn't
need.
Try:
a[a[b==1]<2 | a[b==1]>3] <- NA
Regards,
Richie.
Mathematical Sciences Unit
HSL
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