For the time being  I am assuming the relationship across  variables
is linear.  I want get the values first  and detailed examining  of
the relationship will follow later.

On Mon, Aug 22, 2022 at 12:23 PM Ebert,Timothy Aaron <teb...@ufl.edu> wrote:
>
> I (maybe) agree, but I would go further than that. There are assumptions 
> associated with the test that are missing. It is not clear that the 
> relationships are all linear. Regardless of a "significant outcome" all of 
> the relationships need to be explored in more detail than what is provided in 
> the correlation test.
>
> Multiplicity adjustment as in : 
> https://www.sciencedirect.com/science/article/pii/S0197245600001069 is not an 
> issue that I can see in these data from the information provided. At least 
> not in the same sense as used in the link.
>
> My first guess at the meaning of "multiplicity adjustment" was closer to the 
> experimentwise error rate in a multiple comparison procedure. 
> https://dictionary.apa.org/experiment-wise-error-rateEssentially, the type 1 
> error rate is inflated the more test you do and if you perform enough tests 
> you find significant outcomes by chance alone. There is great significance in 
> the Redskins rule: https://en.wikipedia.org/wiki/Redskins_Rule.
>
> A simple solution is to apply a Bonferroni correction where alpha is divided 
> by the number of comparisons. If there are 250, then 0.05/250 = 0.0002. 
> Another approach is to try to discuss the outcomes in a way that makes sense. 
> What is the connection between a football team's last home game an the 
> election result that would enable me to take another team and apply their 
> last home game result to the outcome of a different election?
>
> Another complication is if variables x2 through x250 are themselves 
> correlated. Not enough information was provided in the problem to know if 
> this is an issue, but 250 orthogonal variables in a real dataset would be a 
> bit unusual considering the experimentwise error rate previously mentioned.
>
> Large datasets can be very messy.
>
>
> Tim
>
> -----Original Message-----
> From: Bert Gunter <bgunter.4...@gmail.com>
> Sent: Monday, August 22, 2022 12:07 PM
> To: Ebert,Timothy Aaron <teb...@ufl.edu>
> Cc: Val <valkr...@gmail.com>; r-help@R-project.org (r-help@r-project.org) 
> <r-help@r-project.org>
> Subject: Re: [R] Correlate
>
> [External Email]
>
> ... But of course the p-values are essentially meaningless without some sort 
> of multiplicity adjustment.
> (search on "multiplicity adjustment" for details). :-(
>
> -- Bert
>
>
> On Mon, Aug 22, 2022 at 8:59 AM Ebert,Timothy Aaron <teb...@ufl.edu> wrote:
> >
> > A somewhat clunky solution:
> > for(i in colnames(dat)){
> >   print(cor.test(dat[,i], dat$x1, method = "pearson", use = 
> > "complete.obs")$estimate)
> >   print(cor.test(dat[,i], dat$x1, method = "pearson", use =
> > "complete.obs")$p.value) }
> >
> > Rather than printing you could set up an array or list to save the results.
> >
> >
> > Tim
> >
> > -----Original Message-----
> > From: R-help <r-help-boun...@r-project.org> On Behalf Of Val
> > Sent: Monday, August 22, 2022 11:09 AM
> > To: r-help@R-project.org (r-help@r-project.org) <r-help@r-project.org>
> > Subject: [R] Correlate
> >
> > [External Email]
> >
> > Hi all,
> >
> > I have a data set with  ~250  variables(columns).  I want to calculate
> > the correlation of  one variable with the rest of the other variables
> > and also want  the p-values  for each correlation.  Please see the
> > sample data and my attempt.  I  have got the correlation but unable to
> > get the p-values
> >
> > dat <- read.table(text="x1 x2 x3 x4
> >            1.68 -0.96 -1.25  0.61
> >           -0.06  0.41  0.06 -0.96
> >               .    0.08  1.14  1.42
> >            0.80 -0.67  0.53 -0.68
> >            0.23 -0.97 -1.18 -0.78
> >           -1.03  1.11 -0.61    .
> >            2.15     .    0.02  0.66
> >            0.35 -0.37 -0.26  0.39
> >           -0.66  0.89   .    -1.49
> >            0.11  1.52  0.73  -1.03",header=TRUE)
> >
> > #change all to numeric
> >     dat[] <- lapply(dat, function(x) as.numeric(as.character(x)))
> >
> >     data_cor <- cor(dat[ , colnames(dat) != "x1"],  dat$x1, method =
> > "pearson", use = "complete.obs")
> >
> > Result
> >               [,1]
> > x2 -0.5845835
> > x3 -0.4664220
> > x4  0.7202837
> >
> > How do I get the p-values ?
> >
> > Thank you,
> >
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