Dear Patrizio and all,
Do you know a similar approach to this, so that *any* function is sequentially
applied on a matrix?
Particularly, instead of wanting to sum columns every 8 rows, how could we
apply a linear regression to the columns of a matrix every 8 rows?
ie, if we have a matrix say of 100 rows and 3 columns- say columns are price,
production cost, desired profit. How can we apply lm(price~production cost
+desired profit) where the data is taken every 10 lines from the matrix, ie we
end up with 10 different regressions?
Any help is welcome,
Thank you very much
Denise
--- On Wed, 7/23/08, Patrizio Frederic <[EMAIL PROTECTED]> wrote:
From: Patrizio Frederic <[EMAIL PROTECTED]>
Subject: Re: [R] sequential sum of a vector...
To: "Shubha Vishwanath Karanth" <[EMAIL PROTECTED]>
Cc: [EMAIL PROTECTED]
Date: Wednesday, July 23, 2008, 8:30 AM
try this
colSums(matrix(x,8))
regards,
PF
+-------------------------------------------------
| Patrizio Frederic
| Research associate in Statistics,
| Department of Economics,
| University of Modena and Reggio Emilia,
| Via Berengario 51,
| 41100 Modena, Italy
|
| tel: +39 059 205 6727
| fax: +39 059 205 6947
| mail: [EMAIL PROTECTED]
+-------------------------------------------------
2008/7/23 Shubha Vishwanath Karanth <[EMAIL PROTECTED]>:
> Hi R,
>
>
>
> Let,
>
>
>
> x=1:80
>
>
>
> I want to sum up first 8 elements of x, then again next 8 elements of x,
> then again another 8 elements..... So, my new vector should look like:
>
> c(36,100,164,228,292,356,420,484,548,612)
>
>
>
> I used:
>
>
>
> aggregate(x,list(rep(1:10,each=8)),sum)[-1]
>
> or
>
> rowsum(x,group=rep(1:10,each=8))
>
>
>
>
>
> But without grouping, can I achieve the required? Any other ways of
> doing this?
>
>
>
> Thanks, Shubha
>
>
>
> This e-mail may contain confidential and/or privileged i...{{dropped:13}}
>
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>
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