Dear Neha gupta,
I hope that I'm not overstepping my role when I say that googling
solutions to specific problems isn't an inefficient way to learn a
programming language, and will probably waste your time in the long run.
There are many good introductions to R.
Best,
John
On 2022-02-17 2:27 p.m., Neha gupta wrote:
Dear John, thanks a lot for the detailed answer.
Yes, I am not an expert in R language and when a problem comes in, I
google it or post it on these forums. (I have just a little bit
experience of ML in R).
On Thu, Feb 17, 2022 at 8:21 PM John Fox <j...@mcmaster.ca
<mailto:j...@mcmaster.ca>> wrote:
Dear Nega gupta,
On 2022-02-17 1:54 p.m., Neha gupta wrote:
> Hello everyone
>
> I have a dataset with output variable "bug" having the following
values (at
> the bottom of this email). My advisor asked me to provide data
distribution
> of bugs with 0 values and bugs with more than 0 values.
>
> data = readARFF("synapse.arff")
> data2 = readARFF("synapse.arff")
> data$bug
> library(tidyverse)
> data %>%
> filter(bug == 0)
> data2 %>%
> filter(bug >= 1)
> boxplot(data2$bug, data$bug, range=0)
>
> But both the graphs are exactly the same, how is it possible?
Where I am
> doing wrong?
As it turns out, you're doing several things wrong.
First, you're not using pipes and filter() correctly. That is, you
don't
do anything with the filtered versions of the data sets. You're
apparently under the incorrect impression that filtering modifies the
original data set.
Second, you're greatly complicating a simple problem. You don't need to
read the data twice and keep two versions of the data set. As well,
processing the data with pipes and filter() is entirely unnecessary.
The
following code works:
with(data, boxplot(bug[bug == 0], bug[bug >= 1], range=0))
Third, and most fundamentally, the parallel boxplots you're apparently
trying to construct don't really make sense. The first "boxplot" is
just
a horizontal line at 0 and so conveys no information. Why not just plot
the nonzero values if that's what you're interested in?
Fourth, you didn't share your data in a convenient form. I was able to
reconstruct them via
bug <- scan()
0 1 0 0 0 1 2 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 2 0 0 0 0 1 0 0
0 0 0
0 4 1 0
0 1 0 0 0 0 0 0 1 0 3 2 0 0 0 0 3 0 0 0 0 2 0 0 0 1 0 0 0 0 1 1
1 0 0
0 0 0 0
1 1 2 1 0 1 0 0 0 2 2 1 1 0 0 0 0 0 0 1 0 0 1 0 0 1 0 0 5 0 0 0
0 0 0
7 0 0 1
0 1 1 0 2 0 3 0 1 0 0 1 0 0 0 0 0 1 1 0 0 0 0 1 0 3 2 1 1 0 0 0
0 0 0
0 1 0 0
0 0 0 0 0 0 0 0 0 1 0 1 0 0 3 0 0 1 0 1 3 0 0 0 0 0 0 0 0 1 0 4
1 1 0
0 0 0 1
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 3 0 1 0 0 0 0 0
data <- data.frame(bug)
Finally, it's better not to post to the list in plain-text email,
rather
than html (as the posting guide suggests).
I hope this helps,
John
>
>
> data$bug
> [1] 0 1 0 0 0 1 2 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 2 0 0 0 0
1 0 0 0 0 0
> 0 4 1 0
> [40] 0 1 0 0 0 0 0 0 1 0 3 2 0 0 0 0 3 0 0 0 0 2 0 0 0 1 0 0 0
0 1 1 1 0 0
> 0 0 0 0
> [79] 1 1 2 1 0 1 0 0 0 2 2 1 1 0 0 0 0 0 0 1 0 0 1 0 0 1 0 0 5
0 0 0 0 0 0
> 7 0 0 1
> [118] 0 1 1 0 2 0 3 0 1 0 0 1 0 0 0 0 0 1 1 0 0 0 0 1 0 3 2 1 1 0
0 0 0 0 0
> 0 1 0 0
> [157] 0 0 0 0 0 0 0 0 0 1 0 1 0 0 3 0 0 1 0 1 3 0 0 0 0 0 0 0 0 1
0 4 1 1 0
> 0 0 0 1
> [196] 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 3 0 1 0 0 0 0 0
>
> [[alternative HTML version deleted]]
>
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--
John Fox, Professor Emeritus
McMaster University
Hamilton, Ontario, Canada
web: https://socialsciences.mcmaster.ca/jfox/
<https://socialsciences.mcmaster.ca/jfox/>
--
John Fox, Professor Emeritus
McMaster University
Hamilton, Ontario, Canada
web: https://socialsciences.mcmaster.ca/jfox/
______________________________________________
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