Hello,
A close parenthesis is missing in the nd if.
for (i in 1:(nrow(PLC_Return)-1)){
if (i == 1){
NUMBER_OF_SHARES[i] = 100/is.na(CLOSE_SHARE_PRICE[i])
} else if(is.na(PLC_Return[i, 1]) == is.na(PLC_Return[i + 1, 1])){
NUMBER_OF_SHARES[i]=0
} else {
NUMBER_OF_SHARES[i] = 100/is.na(CLOSE_SHARE_PRICE[i])
}
}
Hope this helps,
Rui Barradas
Às 13:51 de 13/04/21, e-mail ma015k3113 via R-help escreveu:
Dear All,I have a dataframe with 4 variables and I am trying to calculate how
many shares can be purchased with £100 in the first year when the company was
listed
The data looks like:
COMPANY_NUMBER YEAR_END_DATE CLOSE_SHARE_PRICE NUMBER_OF_SHARES
22705 30/09/2002 NA
0
22705 30/09/2004 NA
0
22705 30/09/2005 6.55
0
22705 30/09/2006 7.5
0
22705 30/09/2007 9.65
0
22705 30/09/2008 6.55
0
1091347 31/01/2010 8.14
0
1091347 31/01/2011 11.38
0
11356069 30/06/2019 1.09
0
SC192761 31/01/2000 NA
0
SC192761 31/01/2001 NA
0
SC192761 31/01/2002 NA
0
SC192761 31/01/2004 NA
0
SC192761 31/01/2005 NA
0
SC192761 31/01/2006 1.09
0
SC192761 31/01/2008 1.24
0
SC192761 31/01/2009 0.9
0
SC192761 31/01/2010 1.14
0
SC192761 31/01/2011 1.25
0
SC192761 31/01/2012 1.29
0
The code I have written is
i <- 0
for (i in 1:(nrow(PLC_Return)-1))
if (i == 1)
{
NUMBER_OF_SHARES[i] = 100/is.na(CLOSE_SHARE_PRICE[i])
} else if
(is.na(PLC_Return[i, 1]) == is.na(PLC_Return[i + 1, 1])
{
NUMBER_OF_SHARES[i]=0
} else
{
NUMBER_OF_SHARES[i] = 100/is.na(CLOSE_SHARE_PRICE[i])
}
The error I get is Error: unexpected 'else' in:
" NUMBER_OF_SHARES[i] = 0
} else"
{NUMBER_OF_SHARES[i] = 100/is.na(CLOSE_SHARE_PRICE[i])}
}
Error: unexpected '}' in "}"
Don't know how to fix it-any help will be appreciated.
Kind regards
Ahson
[[alternative HTML version deleted]]
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
