Hello,
Please cc the list, R-Help is threaded and your doubt and answers might
be of interest to others.
With a vector Y, you want 0 in all Y != l and 1 in all Y == l?
n_l <- function(Y, l) as.integer(Y == l)
Hope this helps,
Rui Barradas
Às 11:26 de 30/01/21, Ablaye Ngalaba escreveu:
Hello Rui,
thank you for answering me.
I compiled your code, it's true that it works but it still gives the
value "3". What I want is to find either 1 if Y==l or 0 in case y
differs from l.
Good day
Le sam. 30 janv. 2021 à 10:42, Ablaye Ngalaba <ablayengal...@gmail.com
<mailto:ablayengal...@gmail.com>> a écrit :
Thanks.
Le sam. 30 janv. 2021 à 05:38, Rui Barradas <ruipbarra...@sapo.pt
<mailto:ruipbarra...@sapo.pt>> a écrit :
Hello,
Maybe this?
n_l <- function(Y, l, na.rm = FALSE) sum(Y == l, na.rm = na.rm)
set.seed(2020)
q <- 6
y <- sample(q, 10, TRUE)
l <- 4
n_l(y, l)
#[1] 3
Hope this helps,
Rui Barradas
Às 14:27 de 29/01/21, Ablaye Ngalaba escreveu:
> Hello,
> please, I need to calculate the indicator function as I
underlined in my
> attached pdf file but I can't define a code in programming
language that
> deals with this case. Please help me with a code whether it's
in python or
> R can help me.
>
>
>
> Sincerely.
>
>
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>
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