Jeremie,
As months have irregular number of dates, one needs to use a function that accounts for that (date libraries and packages have that, one of the earliest for R was my RcppBDT package using Boost Date_Time), or be otherwise clever. Here is a one-liner using the latter approach: seq(as.Date("2010-02-01"), length=24, by="1 month") - 1 See this old StackOverflow answer where I used this before: https://stackoverflow.com/questions/8333838/generate-a-sequence-of-the-last-day-of-the-month-over-two-years Dirk -- https://dirk.eddelbuettel.com | @eddelbuettel | e...@debian.org ______________________________________________ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.