If the forecast.date column is of type character you can use lubridate to do this:
> library(lubridate) > a <- "2020-08-01 12:00:00" > year(a) # [1] 2020 > month(a) # [1] 8 etc On Sun, Aug 2, 2020 at 7:24 PM Philip <herd_...@cox.net> wrote: > Below is some Weather Service data. I would like to parse the forecast > date field into four different columns: > > Year > Month > Day > Hour > > I would like to drop the final four zeros. Any suggestions? > > forecast.date levels lon lat HGT > RH TMP UGRD VGRD > 1 2020-08-01 12:00:00 1000 mb -113.130 33.6335 75.5519 49.6484 305.495 > 1.40155 2.23264 > 2 2020-08-01 12:00:00 1000 mb -113.111 33.5142 75.9582 51.0234 305.245 > 1.65155 2.23264 > 3 2020-08-01 12:00:00 1000 mb -113.092 33.3948 76.3957 52.7734 305.057 > 1.90155 2.23264 > 4 2020-08-01 12:00:00 1000 mb -112.987 33.6495 75.9269 49.1484 305.745 > 1.90155 2.04514 > 5 2020-08-01 12:00:00 1000 mb -112.968 33.5301 76.3019 50.2734 305.495 > 2.08905 1.98264 > > Philip Heinrich > > > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
