I solve this as follows
m2 <- subset(m1,`Classification Description`=="Borrowing from the Public" |
`Classification Description`=="By Other Means" | `Classification
Description`=="Total Surplus (+) or Deficit (-)")
sincerely
Engin YILMAZ
Engin Yılmaz <ispanyol...@gmail.com>, 29 Tem 2020 Çar, 16:57 tarihinde şunu
yazdı:
> Dear
>
> I try to create a new subset from my dataframe.
> My dataframe's name is m1.
> "Classification Description" column has 15 different factors.
> The following code is used creating a subset for 1 factor.
> m2<-m1[m1$`Classification Description` == levels(m1$`Classification
> Description`)[1],]
>
> My aim is to create a subset with 4 different factors. For example,
> levels(m1$`Classification Description`)[1]
> levels(m1$`Classification Description`)[15]
> levels(m1$`Classification Description`)[2]
> levels(m1$`Classification Description`)[4]
>
> I try to following code but it didnt work
>
> m2<-m1[m1$`Classification Description` == levels(m1$`Classification
> Description`)[c(1,15,2,4],]
>
> How can I solve This Problem ?
>
> Example from my dataframe
>
> `Record Date` `Classification Description` `Current Month
> Budget Amount`
> <date> <fct>
> <dbl>
> 1 2019-06-30 Total On-Budget and Off-Budget Results:
> NA
> 2 2019-06-30 Off-Budget Surplus (+) or Deficit (-)
> 41998597035.
> 3 2019-06-30 Total Outlays
> 342428650968.
> 4 2019-06-30 By Other Means
> 51648504883.
> 5 2019-06-30 On-Budget Outlays
> 292169836521.
> 6 2019-06-30 Off-Budget Outlays
> 50258814447.
> 7 2019-06-30 Total Receipts
> 333952332514.
> 8 2019-06-30 On-Budget Surplus (+) or Deficit (-)
> -50474915489.
> 9 2019-06-30 Off-Budget Receipts
> 92257411482
> 10 2019-06-30 Total On-Budget and Off-Budget Financing
> 8476318454
>
>
>
> --
> *Saygılarımla*
> Engin YILMAZ
>
--
*Saygılarımla*
Engin YILMAZ
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