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The obvious solution is: apply( M, 1, min ) * apply( N, 1, max ) but Google sez there is an optimized version useful with large matrices: library( Rfast ) rowMins( M ) * rowMins( N ) (untested) On May 23, 2020 7:30:48 AM PDT, Vahid Borji <vahid.borj...@gmail.com> wrote: >Hi my R friends, > >I have two matrices as follows: > >M<-matrix(c(1,4,1,3,1,4,2,3,1,2,1,2),3) > >1 3 2 2 >4 1 3 1 >1 4 1 2 > >N<-matrix(c(1,1,2,2,3,4,-2,2,1,4,3,-1),3) > >1 2 -2 4 >1 3 2 3 >2 4 1 -1 > >I want to find a vector which is a matrix 1*3 and each of its elements >is >the multiplication of min element of each row of M by the max element >of >the corresponding row of N (for example, the first element of the >vector is >the min element of the first row of matrix M, which is 1, multiply by >the >max element of the first row of matrix N, which is 4, and so the first >element of the vector is 1*4 which is 4). >The final answer is: (1*4, 1*3,1*4)=(4,3,4) > >To find this vector (or matrix) I have written the below code: >c(min(M[1,])*max(N[1,]),min(M[2,])*max(N[2,]),min(M[3,])*max(N[3,])) >But it is so long. could anyone writes a shorter (or simpler, or >easier) >code? > > [[alternative HTML version deleted]] > >______________________________________________ >R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see >https://stat.ethz.ch/mailman/listinfo/r-help >PLEASE do read the posting guide >http://www.R-project.org/posting-guide.html >and provide commented, minimal, self-contained, reproducible code. -- Sent from my phone. Please excuse my brevity. ______________________________________________ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
