Now that you have been shown how to do this, post your (non-working) code next
time. And configure your email program to send plain text so we will see what
you saw.
a$PHENO <- ifelse( a$CURRELIG==1
& a$RTNPTHY==1
, 1
, ifelse( a$PLASER==2
, 2
, -9 ) )
or
a$PHENO <- with( a
, ifelse( CURRELIG==1
& RTNPTHY==1
, 1
, ifelse( PLASER==2
, 2
, -9 ) ) )
On April 8, 2020 1:17:38 PM PDT, Ana Marija <sokovic.anamar...@gmail.com> wrote:
>Hi,
>
>I have a data frame like this:
>
>> head(a)
> FID LASER2 CURRELIG PLASER RTNPTHY
>1 fam1000_G1000 1 1 1 1
>2 fam1001_G1001 1 1 1 1
>3 fam1003_G1003 2 1 2 2
>4 fam1005_G1005 1 1 1 2
>5 fam1009_G1009 1 1 1 2
>6 fam1052_G1052 1 1 1 2
>...
>
>I would like to create a new column called PHENO which would satisfy
>these
>conditions:
>
>if CURRELIG=1 and RTNPTHY=1 than PHENO=1
>if PLASER=2 than PHENO=2
>otherwise is -9
>
>Thanks
>Ana
>
> [[alternative HTML version deleted]]
>
>______________________________________________
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>http://www.R-project.org/posting-guide.html
>and provide commented, minimal, self-contained, reproducible code.
--
Sent from my phone. Please excuse my brevity.
______________________________________________
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
