"But the important point is: If you know the structure of the data you want to parse, then it is best to tell R (or any other language) this structure explicitly. "
Fortune nomination! -- Bert Thu, Dec 19, 2019, 2:49 AM Enrico Schumann <e...@enricoschumann.net> wrote: > > Quoting Eric Berger <ericjber...@gmail.com>: > > > Martin writes: "there's really no reason for going beyond base R" > > > > I disagree. Lubridate is a fantastic package. I use it all the time. It > > makes working with dates really easy, as evidenced by John Kane's > > suggestion. I strongly recommend learning to work with it. > > > > The bottom line: as is often the case, there are many different ways to > > accomplish a task in R. > > I apologise beforehand if this sparks an unnecessary discussion ;-) > > But the important point is: > If you know the structure of the data you want to > parse, then it is best to tell R (or any other language) > this structure explicitly. > > > > On Thu, Dec 19, 2019 at 10:31 AM Martin Maechler < > maech...@stat.math.ethz.ch> > > wrote: > > > >> >>>>> John Kane > >> >>>>> on Tue, 17 Dec 2019 20:28:17 -0500 writes: > >> > >> > library(lubridate) > >> > gs$dat1 <- mdy(gs$date) > >> > >> there's really no reason for going beyond base R. > >> > >> Using the proper format as per Patrick and Peter's advice > >> (below) is perfectly clear and actually > >> more robust (for the next data set etc) > >> than going via "good guessing" in extra packages. > >> > >> > On Tue, 17 Dec 2019 at 18:38, peter dalgaard <pda...@gmail.com> > >> wrote: > >> >> > >> >> ...and switch the order, and use %y for 2-digit years. > >> >> > >> >> > On 17 Dec 2019, at 23:57 , Patrick (Malone Quantitative) < > >> mal...@malonequantitative.com> wrote: > >> >> > > >> >> > Try putting / instead of - in your format, to match the data. > >> >> > > >> >> > On Tue, Dec 17, 2019 at 5:52 PM Val <valkr...@gmail.com> > wrote: > >> >> >> > >> >> >> Hi All, > >> >> >> > >> >> >> I wanted to to convert character date mm/dd/yy to YYYY-mm-dd > >> >> >> The sample data and my attempt is shown below > >> >> >> > >> >> >> gs <-read.table(text="ID date > >> >> >> A1 09/27/03 > >> >> >> A2 05/27/16 > >> >> >> A3 01/25/13 > >> >> >> A4 09/27/19",header=TRUE,stringsAsFactors=F) > >> >> >> > >> >> >> Desired output > >> >> >> ID date d1 > >> >> >> A1 09/27/03 2003-09-27 > >> >> >> A2 05/27/16 2016-05-27 > >> >> >> A3 01/25/13 2012-04-25 > >> >> >> A4 09/27/19 2019-09-27 > >> >> >> > >> >> >> I used this > >> >> >> gs$d1 = as.Date(as.character(gs$date), format = "%Y-%m-%d") > >> >> >> > >> >> >> but I got NA's. > >> >> >> > >> >> >> How do I get my desired result? > >> >> >> Thank you. > >> >> >> > >> >> > >> >> -- > >> >> Peter Dalgaard, Professor, > >> >> Center for Statistics, Copenhagen Business School > >> >> Solbjerg Plads 3, 2000 Frederiksberg, Denmark > >> >> Phone: (+45)38153501 > >> >> Office: A 4.23 > >> >> Email: pd....@cbs.dk Priv: pda...@gmail.com > >> >> > >> > >> > -- > >> > John Kane > >> > Kingston ON Canada > > > > -- > Enrico Schumann > Lucerne, Switzerland > http://enricoschumann.net > > ______________________________________________ > R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > > [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
