> On Oct 9, 2019, at 9:58 AM, Rui Barradas <ruipbarra...@sapo.pt> wrote: > > Hello, > > Here are 3 ways. >
For a large number of bars, sometimes this: plot( y, type='h') # maybe use lwd=5 Chuck > The first are almost the same, they use base graphics. > > x <- 1:6 > y <- c(73,53,42,67,41,50) > > barplot(setNames(y, x)) > > Or > > names(y) <- x > barplot(y) > > > And 3: > > library(ggplot2) > ggplot(data.frame(x, y), aes(x, y)) + > geom_col() > > > Hope this helps, > > Rui Barradas > > > Às 16:12 de 09/10/19, Nick Wray via R-help escreveu: >> I have a vector like say 73,53,42,67,41,50 where these numbers are the >> number of occurrences of the data values 1,2,3,4,5,6 - so in essence I have >> the frequency bit from the hist() function. I can't see an elegant way >> (there are clearly messy workarounds like generating a vector of 73 1's, 53 >> 2's etc) of creating a histogram from this data set. Is there one? >> Thanks Nick Wray >> [[alternative HTML version deleted]] >> ______________________________________________ >> R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see >> https://stat.ethz.ch/mailman/listinfo/r-help >> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html >> and provide commented, minimal, self-contained, reproducible code. >> > ______________________________________________ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
