Hello,

There is a typo, the end colon is missing.

grepl(x, '[^[:alpha:]]')


Hope this helps,

Rui Barradas

Às 21:26 de 28/04/19, Jeff Newmiller escreveu:
Use pattern "[^[:alpha]]" with grepl.

On April 28, 2019 12:50:37 PM PDT, Bert Gunter <bgunter.4...@gmail.com> wrote:
?grepl

gives you a logical vector for indexing.


Bert Gunter

"The trouble with having an open mind is that people keep coming along
and
sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )


On Sun, Apr 28, 2019 at 11:54 AM Graeme Davidson <
graeme.r.david...@gmail.com> wrote:

Hello All,

I can’t find the answer for this so I thought I would ask you lovely
people.

I have a data frame with a column of names, some of which have
non-alphabetical letters.

How, do I extract the row indexes which do not meat the criteria of
alphabetical [[:alpha:]].

Thanks in advance

All the best

Graeme


library(dplyr)
my_df <- data.frame(name1 = c("david", "mo", "ma4tilda856", "steph",
"hadley", "574383"),
                     name2 = c("craig", "salah", "dahl", "paris",
"wick",
"turing"), sex = c("m", "m", "f", "f", "m", "m”))
my_df %>%
   mutate_all(as.character)
         [[alternative HTML version deleted]]

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        [[alternative HTML version deleted]]

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and provide commented, minimal, self-contained, reproducible code.


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and provide commented, minimal, self-contained, reproducible code.

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